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a^3*((5*6*a*b^2)/3) = 0
10*a^4*b^2 = 0
x należy do R
x in (-oo:+oo)
| 6+y=15-4(y+1) | | 0=x^2+2x-528 | | 15p-19p=12 | | 7x-4=3+8x | | 8y+6y=112 | | 9a^2+42a+49= | | 180+0.25x=395 | | 9-3(1+5x)=-19 | | (2u^6/6v^4)^3 | | -18+x=43 | | 2x-8(9-x)=9 | | z/3=-6 | | 4x^2=33x+27 | | 6+7=15-4(y+1) | | 63=70-7y | | 90x^2+75x+10=0 | | 19-8+x=8+7-4 | | -9-8x=-7x | | 7x+5=9x-6 | | 8m=-19+43 | | 1/2(4w-18)=12 | | 4x-3(-2x)=9-14 | | 6p+5=4p-5 | | 8x-2y-3-2x= | | l=23+1.5(9.5) | | l=23+1.5(10) | | l=23+1.5(9) | | .5(x+60)+.9x=79 | | l=23+1.5(8) | | l=23+1.5(7) | | l=23+1.5(6) | | l=23+1.5(5) |